Question
9. Solve the equation \( \sqrt[3]{2 x+1}+3=5 \). What is the value of \( x \) ?
Ask by Lane Wright. in the United States
Jan 23,2025
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Answer
\( x = \frac{7}{2} \) or \( x = 3.5 \)
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To solve the equation \( \sqrt[3]{2 x+1}+3=5 \), first, isolate the cube root: \[ \sqrt[3]{2x+1} = 5 - 3 \] \[ \sqrt[3]{2x+1} = 2 \] Next, cube both sides to eliminate the cube root: \[ 2x + 1 = 2^3 \] \[ 2x + 1 = 8 \] Now, subtract 1 from both sides: \[ 2x = 8 - 1 \] \[ 2x = 7 \] Finally, divide by 2: \[ x = \frac{7}{2} \] Thus, the value of \( x \) is \( \frac{7}{2} \) or 3.5.