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Determinar la longitud de arco de la hélice circular con función vectorial \( r(t)=\cos (t) i+\operatorname{sen}(t) j+t k \) del punto \( (1,0,0) \) al punto \( (1,0,2 \pi) \)

Ask by Christensen Bird. in Colombia
Nov 26,2024

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La longitud de arco de la hélice circular es \( 2\pi \sqrt{2} \).

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Para determinar la longitud de arco de la hélice circular definida por la función vectorial \( r(t)=\cos (t) i+\operatorname{sen}(t) j+t k \), primero necesitamos calcular la derivada de \( r(t) \): \[ r'(t) = -\sin(t) i + \cos(t) j + k. \] La longitud de arco \( L \) entre dos puntos \( t=a \) y \( t=b \) se calcula usando la integral: \[ L = \int_{a}^{b} \|r'(t)\| \, dt. \] Primero, encontramos la norma de \( r'(t) \): \[ \|r'(t)\| = \sqrt{(-\sin(t))^2 + (\cos(t))^2 + (1)^2} = \sqrt{\sin^2(t) + \cos^2(t) + 1} = \sqrt{2}. \] Luego, evaluamos la longitud de arco desde \( t=0 \) hasta \( t=2\pi \): \[ L = \int_{0}^{2\pi} \sqrt{2} \, dt = \sqrt{2} [t]_{0}^{2\pi} = \sqrt{2} (2\pi - 0) = 2\pi\sqrt{2}. \] Por lo tanto, la longitud de arco de la hélice circular entre los puntos dados es \( 2\pi\sqrt{2} \).

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