olve the system by substitution. \[ \qquad \begin{array}{l}y=x-15 \\ y=4 x\end{array} \]
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To solve the system using substitution, we can start with the first equation: \( y = x - 15 \). We will substitute this expression for \( y \) into the second equation \( y = 4x \). So we have: \[ x - 15 = 4x \] Next, we rearrange the equation: \[ -15 = 4x - x \] \[ -15 = 3x \] Dividing both sides by 3, we find: \[ x = -5 \] Now that we have the value of \( x \), we can substitute it back into the first equation to find \( y \): \[ y = -5 - 15 \] \[ y = -20 \] Thus, the solution to the system is \( x = -5 \) and \( y = -20 \), or as an ordered pair: \[ (-5, -20) \]