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6. \( (2 x-3 y)^{2}-(x-y)(3 x+2 y) \)

Ask by Wright Johnston. in South Africa
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The simplified form is \( x^{2}-11xy+11y^{2} \).

Solution

Calculate or simplify the expression \( (2x-3y)^2-(x-y)(3x+2y) \). Simplify the expression by following steps: - step0: Solution: \(\left(2x-3y\right)^{2}-\left(x-y\right)\left(3x+2y\right)\) - step1: Multiply the terms: \(\left(2x-3y\right)^{2}+\left(-x+y\right)\left(3x+2y\right)\) - step2: Expand the expression: \(4x^{2}-12xy+9y^{2}+\left(-x+y\right)\left(3x+2y\right)\) - step3: Expand the expression: \(4x^{2}-12xy+9y^{2}-3x^{2}+xy+2y^{2}\) - step4: Subtract the terms: \(x^{2}-11xy+11y^{2}\) The simplified form of the expression \( (2x-3y)^{2}-(x-y)(3x+2y) \) is \( x^{2}-11xy+11y^{2} \).

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Beyond the Answer

To simplify the expression \( (2x - 3y)^{2} - (x - y)(3x + 2y) \), let's first expand both parts. Expanding \( (2x - 3y)^{2} \): \[ (2x - 3y)^{2} = 4x^{2} - 12xy + 9y^{2} \] Now, expanding \( (x - y)(3x + 2y) \): \[ (x - y)(3x + 2y) = 3x^{2} + 2xy - 3xy - 2y^{2} = 3x^{2} - xy - 2y^{2} \] Now, substitute the expanded expressions back into the original expression: \[ (4x^{2} - 12xy + 9y^{2}) - (3x^{2} - xy - 2y^{2}) \] Distributing the negative sign: \[ 4x^{2} - 12xy + 9y^{2} - 3x^{2} + xy + 2y^{2} \] Now, combine like terms: \[ (4x^{2} - 3x^{2}) + (-12xy + xy) + (9y^{2} + 2y^{2}) = x^{2} - 11xy + 11y^{2} \] The final simplified expression is: \[ \boxed{x^{2} - 11xy + 11y^{2}} \]

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