(3) $$ \frac{3^{x+3} \cdot 18^{x}}{6^{x+1} \cdot 9^{x+1}} $$

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Calculate or simplify the expression $$ (3^(x+3) * 18^x)/(6^(x+1) * 9^(x+1)) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{\left(3^{x+3}	imes 18^{x}ight)}{\left(6^{x+1}	imes 9^{x+1}ight)}$$
- step1: Remove the parentheses:
  $$\frac{3^{x+3}	imes 18^{x}}{6^{x+1}	imes 9^{x+1}}$$
- step2: Factor the expression:
  $$\frac{3^{x+3}	imes 18^{x}}{3^{x+1}	imes 2^{x+1}	imes 9^{x+1}}$$
- step3: Reduce the fraction:
  $$\frac{3^{2}	imes 18^{x}}{2^{x+1}	imes 9^{x+1}}$$
- step4: Factor the expression:
  $$\frac{3^{2}	imes 18^{x}}{2^{x+1}	imes 3^{2}	imes 9^{x}}$$
- step5: Reduce the fraction:
  $$\frac{18^{x}}{2^{x+1}	imes 9^{x}}$$
- step6: Factor the expression:
  $$\frac{2^{x}	imes 9^{x}}{2^{x+1}	imes 9^{x}}$$
- step7: Reduce the fraction:
  $$\frac{1}{2}$$
The simplified form of the expression $$ \frac{3^{x+3} \cdot 18^{x}}{6^{x+1} \cdot 9^{x+1}} $$ is $$ \frac{1}{2} $$ or 0.5.
The simplified form of the expression is $$ \frac{1}{2} $$ or 0.5.

(3)

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