g) \( 2[2 y-3(y+1)]+3[y+2(3 y-4)] \)
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Answer
Solution
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Bonus Knowledge
To solve the expression \( 2[2y - 3(y+1)] + 3[y + 2(3y - 4)] \), let's simplify it step by step! First, focus on the inside brackets. The term \( 3(y + 1) \) simplifies to \( 3y + 3 \). So, it's \( 2y - 3y - 3 \) which results in \( -y - 3 \). Now, distribute the \( 2 \): \[ 2(-y - 3) = -2y - 6. \] Now for the second part \( 2(3y - 4) \): it simplifies to \( 6y - 8 \). Thus, \( y + 6y - 8 \) equals \( 7y - 8 \). Now, distribute the \( 3 \): \[ 3(7y - 8) = 21y - 24. \] Combining the two parts: \[ -2y - 6 + 21y - 24 = (21y - 2y) + (-6 - 24) = 19y - 30. \] So, the final solution is \( 19y - 30 \)!