h) $$ \left(+\frac{9}{4}\right)^{-2}= $$

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Vamos calcular a expressão $$ \left(+\frac{9}{4}\right)^{-2} $$.

Para resolver isso, utilizamos a propriedade das potências que diz que $$ a^{-n} = \frac{1}{a^n} $$. Portanto, podemos reescrever a expressão como:

$$
\left(+\frac{9}{4}\right)^{-2} = \frac{1}{\left(+\frac{9}{4}\right)^{2}}
$$

Agora, vamos calcular $$ \left(+\frac{9}{4}\right)^{2} $$:
Calculate the value by following steps:
- step0: Calculate:
  $$\left(\frac{9}{4}\right)^{2}$$
- step1: Use the properties of exponents:
  $$\frac{9^{2}}{4^{2}}$$
- step2: Evaluate the power:
  $$\frac{81}{4^{2}}$$
- step3: Evaluate the power:
  $$\frac{81}{16}$$
Calculando $$ \left(+\frac{9}{4}\right)^{2} $$, obtemos:

$$
\left(+\frac{9}{4}\right)^{2} = \frac{81}{16}
$$

Agora, substituímos isso de volta na expressão original:

$$
\left(+\frac{9}{4}\right)^{-2} = \frac{1}{\frac{81}{16}} = \frac{16}{81}
$$

Portanto, o resultado final é:

$$
\left(+\frac{9}{4}\right)^{-2} = \frac{16}{81}
$$
$$ \left(+\frac{9}{4}\right)^{-2} = \frac{16}{81} $$

h)

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