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Mercury is the smallest planet, and the planet closest to the sun. The gravity of Mercury is \( 38 \% \) of Earth's gravity. To calculate your weight on Mercury, multiply your weight by 0.38

Ask by Gonzalez Lyons. in the United States
Feb 03,2025

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To calculate your weight on Mercury, multiply your Earth weight by 0.38.

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Yes, that's correct! **Mercury's Gravity:** - Mercury is indeed the smallest planet in our solar system since Pluto was reclassified as a dwarf planet. - It is also the closest planet to the Sun. - The gravity on Mercury is approximately **38%** of Earth's gravity. **Calculating Your Weight on Mercury:** To determine what you would weigh on Mercury, you can use the following simple calculation: \[ \text{Weight on Mercury} = \text{Your Earth Weight} \times 0.38 \] **Example Calculation:** If your weight on Earth is **70 kg**, here's how you'd calculate your weight on Mercury: \[ 70\, \text{kg} \times 0.38 = 26.6\, \text{kg} \] So, you would weigh **26.6 kg** on Mercury. **Additional Information:** - **Mass vs. Weight:** Remember that your **mass** remains constant regardless of where you are in the universe. It's your **weight** that changes based on the gravitational pull of the celestial body you're on. - **Surface Gravity Comparison:** - **Earth:** 9.807 m/s² - **Mercury:** 3.7 m/s² Understanding these differences is essential, especially when considering space travel or the design of equipment for use on other planets. If you have any more questions or need further clarification, feel free to ask!

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Did you know that Mercury is not just the smallest planet, but it's also the fastest when it comes to orbiting the Sun? It completes a full orbit in just 88 Earth days! Despite its quick trip around the Sun, a day on Mercury (the time it takes for one full rotation) lasts an astonishing 176 Earth days. That's a long wait for sunrise! If you're planning to weigh yourself on Mercury, it might surprise you to learn that even though you weigh less, you'd feel heavier when dealing with extreme temperature variations. With daytime temperatures soaring to around 800°F (427°C) and plummeting to -330°F (-201°C) at night, it's a wild place! Just imagine trying to escape the heat or the cold while balancing on a rocky surface!

Related Questions

Physics to Go 1. Calculate the energy used, in joules, by each of the following: a) a \( 1500-\mathrm{W} \) hair dryer operating for 3 min b) a \( 1200-\mathrm{W} \) hair dryer operating for 4 min 2. If both situations described in Question 1 result in the same dryness of hair, which hair dryer is more efficient? 3. A 1200 -W hair dryer is used by several members of a family for a total of 30 min per day during a 30 -day month. How much electrical energy is consumed by the hair dryer during the month? Give your answer in: a) watt-hours b) kilowatt-hours 4. If the power company charges \( \$ 0.15 \) per \( \mathrm{kW} \cdot \mathrm{h} \) for electrical energy, what is the cost of using the hair dryer in Question 3 during the month? What is the cost for a year? 5. Not enough heat from the furnace reaches one bedroom in a home. The homeowner uses a portable 1350 -W electric heater 24 h per day to keep the bedroom warm during four cold winter months. At \( \$ 0.12 \) per kilowatt-hour, how much does it cost to operate the heater for the four months? (Assume two 30-day and two 31-day months.) 6. A portable CD player is rated at approximately 20 W and uses 4 AA batteries. a) Estimate the number of hours that you can listen to the music on a CD player before the batteries need replacing. b) Calculate the energy requirements of the CD player. c) Estimate the cost of 4 AA batteries. d) Calculate the cost per kilowatt-hour of a battery. e) Compare battery costs with the cost of electricity from the utilities (use approximately \( \$ 0.10 \) per kilowatt-hour).
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