5) \( \quad 2: 3^{2 x+1}=510 \)
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To solve the equation \( 2: 3^{2x+1} = 510 \), we can rewrite it as \( \frac{2}{3^{2x+1}} = 510 \). Multiplying both sides by \( 3^{2x+1} \) gives us \( 2 = 510 \cdot 3^{2x+1} \). Dividing both sides by 510, we get \( 3^{2x+1} = \frac{2}{510} = \frac{1}{255} \). Next, we can rewrite \( \frac{1}{255} \) as \( 3^{2x+1} = 3^{-5} \) because \( 255 = 3^5 \cdot 5 \). This means that \( 2x + 1 = -5 \). Solving for \( x \), we subtract 1 from both sides to get \( 2x = -6 \), and dividing by 2, we find \( x = -3 \). So, the solution is \( x = -3 \).