How many terms are $$ \begin{array}{l}3 a b-3 b-a+6 \ 5(3 t+s)-2 t^{2} \ (9 z+6 x)(3 x-2 z\end{array} $$

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Let's determine the number of terms in each of the given expressions:

1. **Expression 1: $$3ab - 3b - a + 6$$**
   
   - **Terms:** $$3ab$$, $$-3b$$, $$-a$$, $$+6$$
   - **Total Terms:** **4**

2. **Expression 2: $$5(3t + s) - 2t^2$$**
   
   - First, distribute the 5:
     $$
     5 \times 3t = 15t \
     5 \times s = 5s
     $$
   - Now, the expression becomes:
     $$
     15t + 5s - 2t^2
     $$
   - **Terms:** $$15t$$, $$5s$$, $$-2t^2$$
   - **Total Terms:** **3**

3. **Expression 3: $$(9z + 6x)(3x - 2z)$$**
   
   - Expand the product using the distributive property:
     $$
     9z \times 3x = 27zx \
     9z \times (-2z) = -18z^2 \
     6x \times 3x = 18x^2 \
     6x \times (-2z) = -12xz
     $$
   - Combine like terms ($$27zx$$ and $$-12xz$$ are like terms):
     $$
     (27zx - 12zx) + (-18z^2) + 18x^2 = 15zx - 18z^2 + 18x^2
     $$
   - **Terms:** $$15zx$$, $$-18z^2$$, $$18x^2$$
   - **Total Terms:** **3**

**Summary:**
- **First Expression:** 4 terms
- **Second Expression:** 3 terms
- **Third Expression:** 3 terms
- **First Expression:** 4 terms - **Second Expression:** 3 terms - **Third Expression:** 3 terms

How many terms are \( \begin{array}{l}3 a b-3 b-a+6 \\ 5(3 t+s)-2 t^{2} \\ (9 z+6 x)(3 x-2 z\end{array} \)

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