5 Use the inverse of the distributive property to complete the following. a \( (4 \times 12)+(4 \times 6)=4(\square+\square)=4 \times \square=\square \) b \( (25 \times 30)-(25 \times 2)=25(\square-\square)=\square \times \square=\square \)

Let's apply the inverse of the distributive property to each part of the problem. The inverse distributive property allows us to factor out a common factor from each term in an expression. ### Part a Given: \[ (4 \times 12) + (4 \times 6) \] **Step 1:** Factor out the common factor \(4\): \[ 4 \times (12 + 6) \] **Step 2:** Simplify inside the parentheses: \[ 4 \times 18 \] **Step 3:** Calculate the final product: \[ 4 \times 18 = 72 \] **Completed Expression:** \[ (4 \times 12) + (4 \times 6) = 4(12 + 6) = 4 \times 18 = 72 \] ### Part b Given: \[ (25 \times 30) - (25 \times 2) \] **Step 1:** Factor out the common factor \(25\): \[ 25 \times (30 - 2) \] **Step 2:** Simplify inside the parentheses: \[ 25 \times 28 \] **Step 3:** Calculate the final product: \[ 25 \times 28 = 700 \] **Completed Expression:** \[ (25 \times 30) - (25 \times 2) = 25(30 - 2) = 25 \times 28 = 700 \]