1. For how long did Eze travel 10 km at the speed of \( 20 \mathrm{~km} / \mathrm{hr} \) ? (N.C.E.E 2011) [a] 60 min . [b] 30 min . [c] 15 min [d] 10 min [e] 2 min 2. \( \mathrm{A}, \mathrm{B} \) and \( C \) are three houses in this order along a street in Lagos. The distance from \( A \) to \( B \) is 120 m and the distance from \( B \) to \( C \) is two-third of that of A and B. What is the distance between A and C? (N.C.E.E 2011) [a] 360 m [b] 240 m [c] 200 m [d] 80 m [e] 40 m An athlete runs \( q \mathrm{~km} \) in t hour. His speed is (N.C.E.E 2009) [a] qt km per hour [b] \( \frac{q}{t} \mathrm{~km} \) per hour c] \( t \mathrm{~km} \) per hour \( \mathrm{q}[\mathrm{d}](q-t) \mathrm{km} \) per hour ] \( (q+t) \mathrm{km} \) per hour

Let's address each question one by one: --- **1. For how long did Eze travel 10 km at the speed of \( 20 \mathrm{~km} / \mathrm{hr} \)?** **Options:** [a] 60 min [b] 30 min [c] 15 min [d] 10 min [e] 2 min **Solution:** Time is calculated using the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{10 \, \text{km}}{20 \, \text{km/hr}} = 0.5 \, \text{hours} \] Convert hours to minutes: \[ 0.5 \, \text{hours} \times 60 \, \text{min/hr} = 30 \, \text{minutes} \] **Answer:** **[b] 30 min** --- **2. \( A \), \( B \), and \( C \) are three houses in this order along a street in Lagos. The distance from \( A \) to \( B \) is 120 m and the distance from \( B \) to \( C \) is two-thirds of that of \( A \) to \( B \). What is the distance between \( A \) and \( C \)?** **Options:** [a] 360 m [b] 240 m [c] 200 m [d] 80 m [e] 40 m **Solution:** Distance from \( B \) to \( C \): \[ \frac{2}{3} \times 120 \, \text{m} = 80 \, \text{m} \] Total distance from \( A \) to \( C \): \[ 120 \, \text{m} + 80 \, \text{m} = 200 \, \text{m} \] **Answer:** **[c] 200 m** --- **3. An athlete runs \( q \mathrm{~km} \) in \( t \) hours. His speed is:** **Options:** [a] \( qt \) km per hour [b] \( \frac{q}{t} \) km per hour [c] \( t \) km per hour [d] \( q - t \) km per hour [e] \( q + t \) km per hour **Solution:** Speed is calculated using the formula: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{q \, \text{km}}{t \, \text{hr}} = \frac{q}{t} \, \text{km/hr} \] **Answer:** **[b] \( \frac{q}{t} \) km per hour** ---