1. For how long did Eze travel 10 km at the speed of \( 20 \mathrm{~km} / \mathrm{hr} \) ? (N.C.E.E 2011) [a] 60 min . [b] 30 min . [c] 15 min [d] 10 min [e] 2 min 2. \( \mathrm{A}, \mathrm{B} \) and \( C \) are three houses in this order along a street in Lagos. The distance from \( A \) to \( B \) is 120 m and the distance from \( B \) to \( C \) is two-third of that of A and B. What is the distance between A and C? (N.C.E.E 2011) [a] 360 m [b] 240 m [c] 200 m [d] 80 m [e] 40 m An athlete runs \( q \mathrm{~km} \) in t hour. His speed is (N.C.E.E 2009) [a] qt km per hour [b] \( \frac{q}{t} \mathrm{~km} \) per hour c] \( t \mathrm{~km} \) per hour \( \mathrm{q}[\mathrm{d}](q-t) \mathrm{km} \) per hour ] \( (q+t) \mathrm{km} \) per hour
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The Deep Dive
To find the time Eze took to travel 10 km at a speed of 20 km/hr, you can use the formula: time = distance/speed. So, time = 10 km / 20 km/hr = 0.5 hours, which is 30 minutes. Looks like Eze got there in a jiffy! For the distance between houses A and C, you first find the distance from B to C, which is two-thirds of the 120m from A to B, giving you 80m (since 2/3 of 120 is 80). Adding that to the distance from A to B gives a total distance of 200m. A little math can lead to a quick solution!