Question
Find an equation in rectangular coordinates for the cylindrical equation \( r=3 \)
Ask by Bowers Hills. in the United States
Jan 27,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The rectangular equation is \( x^2 + y^2 = 9 \).
Solution
In cylindrical coordinates, \( r = 3 \) represents all points that are at a distance of 3 units from the origin in the \( xy \)-plane, extending infinitely in the \( z \)-direction. To convert this to rectangular (Cartesian) coordinates, we use the relationship between cylindrical and rectangular coordinates:
\[
x = r \cos \theta
\]
\[
y = r \sin \theta
\]
\[
z = z
\]
Given \( r = 3 \), we can express \( x \) and \( y \) in terms of \( r \):
\[
x^2 + y^2 = r^2
\]
Substituting \( r = 3 \):
\[
x^2 + y^2 = 3^2
\]
\[
x^2 + y^2 = 9
\]
This equation represents a cylinder of radius 3 centered along the \( z \)-axis in rectangular coordinates.
**Answer:**
After simplifying, an equivalent rectangular equation is x² + y² = 9.
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Beyond the Answer
In cylindrical coordinates, the equation \( r = 3 \) represents a vertical cylinder with a radius of 3 centered around the z-axis. To convert this into rectangular coordinates, we can use the relationship \( r = \sqrt{x^2 + y^2} \). Thus, the equation becomes \( \sqrt{x^2 + y^2} = 3 \). Squaring both sides leads to \( x^2 + y^2 = 9 \), which is the equation of a circle in the xy-plane with a radius of 3 centered at the origin. This equation describes all points that are 3 units from the z-axis, effectively illustrating our cylindrical notion in a flat world!