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Find an equation in rectangular coordinates for the cylindrical equation \( r=3 \)

Ask by Bowers Hills. in the United States
Jan 27,2025

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Answer

The rectangular equation is \( x^2 + y^2 = 9 \).

Solution

In cylindrical coordinates, \( r = 3 \) represents all points that are at a distance of 3 units from the origin in the \( xy \)-plane, extending infinitely in the \( z \)-direction. To convert this to rectangular (Cartesian) coordinates, we use the relationship between cylindrical and rectangular coordinates: \[ x = r \cos \theta \] \[ y = r \sin \theta \] \[ z = z \] Given \( r = 3 \), we can express \( x \) and \( y \) in terms of \( r \): \[ x^2 + y^2 = r^2 \] Substituting \( r = 3 \): \[ x^2 + y^2 = 3^2 \] \[ x^2 + y^2 = 9 \] This equation represents a cylinder of radius 3 centered along the \( z \)-axis in rectangular coordinates. **Answer:** After simplifying, an equivalent rectangular equation is x² + y² = 9.

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Beyond the Answer

In cylindrical coordinates, the equation \( r = 3 \) represents a vertical cylinder with a radius of 3 centered around the z-axis. To convert this into rectangular coordinates, we can use the relationship \( r = \sqrt{x^2 + y^2} \). Thus, the equation becomes \( \sqrt{x^2 + y^2} = 3 \). Squaring both sides leads to \( x^2 + y^2 = 9 \), which is the equation of a circle in the xy-plane with a radius of 3 centered at the origin. This equation describes all points that are 3 units from the z-axis, effectively illustrating our cylindrical notion in a flat world!

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