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For the universal set, \( U=\{f, g, h, p, q, r, x\} \), complete the parts below. Write your answers in roster form or as \( \varnothing \). (a) Suppose \( A=\{f, g, q, r, x\} \). Then what is \( A^{\prime} \) ? \( A^{\prime}=\square \) (b) Suppose we know that \( B^{\prime}=\{p, q, r\} \). Then what would \( B \) have to be? \( B=\square \)

Ask by Norton Cox. in the United States
Feb 03,2025

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Tutor-Verified Answer

Answer

\( A^{\prime} = \{h, p\} \) \( B = \{f, g, h, x\} \)

Solution

Let's solve each part step by step. ### Part (a) **Given:** - Universal set \( U = \{f, g, h, p, q, r, x\} \) - Set \( A = \{f, g, q, r, x\} \) **Find \( A^{\prime} \) (the complement of \( A \)):** The complement of \( A \) consists of all elements in \( U \) that are not in \( A \). \[ A^{\prime} = U \setminus A = \{h, p\} \] ### Part (b) **Given:** - \( B^{\prime} = \{p, q, r\} \) **Find \( B \):** Since \( B^{\prime} \) is the complement of \( B \), \( B \) consists of all elements in \( U \) that are not in \( B^{\prime} \). \[ B = U \setminus B^{\prime} = \{f, g, h, x\} \] ### Final Answers (a) \( A^{\prime} = \{h, p\} \) (b) \( B = \{f,\, g,\, h,\, x\} \)

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To find \( A^{\prime} \), we need to identify the elements in the universal set \( U \) that are not in set \( A \). Since \( A=\{f, g, q, r, x\} \), the elements in \( A^{\prime} \) would be those from \( U \) that are not included in \( A \). (a) Thus, the elements of \( U \) that are not in \( A \) are \( \{h, p\} \). So, \( A^{\prime} = \{h, p\} \). (b) Since we know \( B^{\prime} = \{p, q, r\} \) is the complement of \( B \), this means that \( B \) will include all elements in \( U \) not in \( B^{\prime} \). The universal set \( U \) minus elements of \( B^{\prime} \) results in \( B = \{f, g, h, x\} \).

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