Show that \( x=a \log a^{2} \)

To show that \( x = a \log a^2 \), we can start by simplifying the right-hand side of the equation. Using the logarithmic identity that states \( \log a^b = b \log a \), we have: \[ \log a^2 = 2 \log a \] Now, substituting this back into our equation gives: \[ x = a \log a^2 = a \cdot (2 \log a) \] This can further be simplified to: \[ x = 2a \log a \] Thus, the expression simplifies to \( x = 2a \log a \). However, the original request seems to suggest a transformation rather than an equality. Given the context and verifying through substitution or manipulation does not directly yield \( x = a \log a^2 \) as typically \( x \) will be defined as \( 2a \log a \) through the simplification. Therefore, you may want to check the expression or the context from which \( x \) is derived.