Uest 15 What method of solving a quadratic equation is shown here? $$ \begin{array}{l}x^{2}+7 x+12=0 \ (x+3)(x+4)=0 \ x+3=0 \quad x+4=0 \ x=-3 \quad x=-4 \ ext { A. quadratic formula } \ ext { B. grouping } \ ext { C. factoring }\end{array} $$ $$ \begin{array}{l}x=\end{array} $$

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Uest 15 What method of solving a quadratic equation is shown here? $$ \begin{array}{l}x^{2}+7 x+12=0 \ (x+3)(x+4)=0 \ x+3=0 \quad x+4=0 \ x=-3 \quad x=-4 \ 	ext { A. quadratic formula } \ 	ext { B. grouping } \ 	ext { C. factoring }\end{array} $$ $$ \begin{array}{l}x=\end{array} $$

UpStudy AI · Accepted Answer

The method of solving the quadratic equation shown in your example is **C. factoring**.

The equation $$x^2 + 7x + 12 = 0$$ is factored into $$(x + 3)(x + 4) = 0$$, and then the solutions are found by setting each factor equal to zero.

So, the answer is:

**C. factoring**

And the solutions are $$x = -3$$ and $$x = -4$$.
The method is C. factoring. Solutions: $$x = -3$$ and $$x = -4$$.

Uest 15
What method of solving a quadratic equation is shown here?

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