Question
Chris had \( 3^{\frac{1}{6}} \) pounds of chocolate candies. If he ate \( \frac{1}{10} \) of them over the weekend how much did he eat?
Ask by Lane Wade. in the United States
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
Chris ate approximately 0.12 pounds of chocolate candies over the weekend.
Solution
To find out how much Chris ate, we need to calculate \( \frac{1}{10} \) of \( 3^{\frac{1}{6}} \) pounds of chocolate candies.
Let's calculate this:
\[ \frac{1}{10} \times 3^{\frac{1}{6}} \]
We can simplify this expression by first calculating \( 3^{\frac{1}{6}} \) and then multiplying it by \( \frac{1}{10} \).
Calculate the value by following steps:
- step0: Calculate:
\(\frac{1}{10}\times 3^{\frac{1}{6}}\)
- step1: Multiply:
\(\frac{3^{\frac{1}{6}}}{10}\)
- step2: Simplify:
\(\frac{\sqrt[6]{3}}{10}\)
Chris ate approximately 0.120094 pounds of chocolate candies over the weekend.
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Simplify this solution Bonus Knowledge
To find out how much chocolate candies Chris ate, we can calculate \( \frac{1}{10} \) of \( 3^{\frac{1}{6}} \). First, we compute \( \frac{1}{10} \times 3^{\frac{1}{6}} \): \[ \text{Amount eaten} = \frac{1}{10} \times 3^{\frac{1}{6}} \] This gives us: \[ \text{Amount eaten} = \frac{3^{\frac{1}{6}}}{10} \] So, Chris ate \( \frac{3^{\frac{1}{6}}}{10} \) pounds of chocolate candies over the weekend. That's roughly 0.0456 pounds if you prefer it in decimal form, but that tiny bit of chocolate is still sweet!
