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graph the system of \( 2 x+y=4 \quad \) write the \( \begin{array}{ll}y=\frac{1}{2} x-1 & \text { solution }\end{array} \)

Ask by Boyd Morrison. in the United States
Dec 30,2024

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Answer

The system of equations has one solution at the point (2, 0).

Solution

Certainly! Let's analyze and graph the system of equations you've provided. ## System of Equations You have the following system: \[ \begin{cases} 2x + y = 4 \\ y = \frac{1}{2}x - 1 \end{cases} \] ## Solving the System To find the solution to this system, we'll use the substitution method. 1. **From the second equation**, we already have \( y \) expressed in terms of \( x \): \[ y = \frac{1}{2}x - 1 \] 2. **Substitute** this expression for \( y \) into the first equation: \[ 2x + \left(\frac{1}{2}x - 1\right) = 4 \] 3. **Combine like terms**: \[ 2x + \frac{1}{2}x - 1 = 4 \] \[ \frac{5}{2}x - 1 = 4 \] 4. **Solve for \( x \)**: \[ \frac{5}{2}x = 5 \] \[ x = 2 \] 5. **Find \( y \)** using the second equation: \[ y = \frac{1}{2}(2) - 1 = 1 - 1 = 0 \] **Solution:** The system has a single solution at the point \( (2, 0) \). ## Graphing the System Let's graph both equations to visualize their intersection. ### 1. Graph of \( 2x + y = 4 \) Rearrange to slope-intercept form (\( y = mx + b \)): \[ y = -2x + 4 \] - **Slope (m):** -2 - **Y-intercept (b):** 4 **Points to Plot:** - When \( x = 0 \), \( y = 4 \) → Point \( (0, 4) \) - When \( x = 2 \), \( y = 0 \) → Point \( (2, 0) \) ### 2. Graph of \( y = \frac{1}{2}x - 1 \) - **Slope (m):** \( \frac{1}{2} \) - **Y-intercept (b):** -1 **Points to Plot:** - When \( x = 0 \), \( y = -1 \) → Point \( (0, -1) \) - When \( x = 2 \), \( y = 0 \) → Point \( (2, 0) \) ### Graph Illustration Below is a graphical representation of the system: ```plaintext y | 5 | 4 |● (2,0) 3 | 2 | 1 | 0 |---------●--------- x 0 1 2 3 4 ``` In a more detailed graph: - The line \( y = -2x + 4 \) passes through \( (0, 4) \) and \( (2, 0) \). - The line \( y = \frac{1}{2}x - 1 \) passes through \( (0, -1) \) and \( (2, 0) \). - Both lines intersect at \( (2, 0) \), which is the solution to the system. ### Visual Graph For a clearer visual, here's a graph created using [Desmos](https://www.desmos.com/calculator): ![Graph of the system](https://i.imgur.com/yourimageurl.png) *(Please replace the image URL with an actual graph if needed.)* ## Conclusion The system of equations: \[ \begin{cases} 2x + y = 4 \\ y = \frac{1}{2}x - 1 \end{cases} \] has a single solution at the point \( (2, 0) \), where both lines intersect on the graph.

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Extra Insights

To graph the system of equations, start by identifying the key points for \( y = 2 - 2x \) and \( y = \frac{1}{2} x - 1 \). For \( 2x + y = 4 \), you can find the intercepts by setting \( x = 0 \) and \( y = 0 \). The y-intercept is \( (0, 4) \) and the x-intercept is \( (2, 0) \). For the second equation, if you set \( x = 0 \), then \( y = -1 \) and if you set \( y = 0 \), then \( x = 2 \). Plotting these points and drawing straight lines through them will provide a clear visual representation of the system. Checking your solutions is essential! A common mistake when graphing is not calculating the correct intercepts or mislabeling them. Make sure to double-check each intercept by substituting back into the original equations. Also, don’t forget to label your axes and the lines for clarity; a little bit of neatness goes a long way in making your graph understandable and properly presenting the solution set.

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