Question
B A box contains ten cards labeled \( Q, R, S, T, U, V, W, X, Y \), and \( Z \). One card will be randomly chosen What is the probability of choosing a letter from \( U \) to \( Z \) ? Write your answer as a fraction in simplest form.
Ask by Ramirez Ortega. in the United States
Feb 13,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The probability is \( \frac{3}{5} \).
Solution
There are 10 cards in total. The letters from U to Z are U, V, W, X, Y, and Z, which makes 6 letters.
Thus, the probability of choosing a card labeled with a letter from U to Z is 6/10. Simplifying this fraction gives 3/5.
Reviewed and approved by the UpStudy tutoring team
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Simplify this solution Extra Insights
To find the probability of choosing a letter from \( U \) to \( Z \) from the ten cards, we first identify how many favorable outcomes there are. The letters \( U, V, W, X, Y, \) and \( Z \) total 6 outcomes. Now, the total number of cards is 10. The probability is calculated by dividing the number of favorable outcomes by the total number of outcomes: \[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{6}{10} = \frac{3}{5} \] So, the probability of choosing a letter from \( U \) to \( Z \) is \( \frac{3}{5} \).
