Find $$ a_{3}, a_{4}, a_{5} $$, and $$ a_{6} $$. $$ a_{1}=-3 $$ $$ a_{2}=3 $$ $$ a_{n}=-a_{n-1}+2 a_{n-2} $$ Write your answers as integers or fractions in simplest form. $$ a_{3}=\square $$ $$ a_{4}= $$ $$ a_{5}=\square $$ $$ a_{6}=\square $$

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To find the values of $$ a_3, a_4, a_5, $$ and $$ a_6 $$ using the recurrence relation $$ a_n = -a_{n-1} + 2a_{n-2} $$, we will calculate each term step by step.

We are given:
- $$ a_1 = -3 $$
- $$ a_2 = 3 $$

Now we can calculate $$ a_3 $$:

$$
a_3 = -a_2 + 2a_1 = -3 + 2(-3) = -3 - 6 = -9
$$

Next, we calculate $$ a_4 $$:

$$
a_4 = -a_3 + 2a_2 = -(-9) + 2(3) = 9 + 6 = 15
$$

Now we calculate $$ a_5 $$:

$$
a_5 = -a_4 + 2a_3 = -15 + 2(-9) = -15 - 18 = -33
$$

Finally, we calculate $$ a_6 $$:

$$
a_6 = -a_5 + 2a_4 = -(-33) + 2(15) = 33 + 30 = 63
$$

Now we can summarize the results:

$$
a_3 = -9
$$
$$
a_4 = 15
$$
$$
a_5 = -33
$$
$$
a_6 = 63
$$

Thus, the final answers are:
- $$ a_3 = -9 $$
- $$ a_4 = 15 $$
- $$ a_5 = -33 $$
- $$ a_6 = 63 $$
$$ a_3 = -9 $$ $$ a_4 = 15 $$ $$ a_5 = -33 $$ $$ a_6 = 63 $$

Find \( a_{3}, a_{4}, a_{5} \), and \( a_{6} \). \( a_{1}=-3 \) \( a_{2}=3 \) \( a_{n}=-a_{n-1}+2 a_{n-2} \) Write your answers as integers or fractions in simplest form. \( a_{3}=\square \) \( a_{4}= \) \( a_{5}=\square \) \( a_{6}=\square \)

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