c) $$ \left(k^{2}+2 k+1\right)\left(k^{2}-2 k-1\right) $$

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Calculate or simplify the expression $$ (k^2+2k+1)(k^2-2k-1) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\left(k^{2}+2k+1ight)\left(k^{2}-2k-1ight)$$
- step1: Apply the distributive property:
  $$k^{2}	imes k^{2}-k^{2}	imes 2k-k^{2}	imes 1+2k	imes k^{2}-2k	imes 2k-2k	imes 1+1	imes k^{2}-1	imes 2k-1	imes 1$$
- step2: Multiply the terms:
  $$k^{4}-2k^{3}-k^{2}+2k^{3}-4k^{2}-2k+k^{2}-2k-1$$
- step3: Collect like terms:
  $$k^{4}-4k^{2}-4k-1$$
The expansion of the given expression $$ \left(k^{2}+2 k+1ight)\left(k^{2}-2 k-1ight) $$ is $$ k^{4}-4k^{2}-4k-1 $$.
The expression simplifies to $$ k^{4} - 4k^{2} - 4k - 1 $$.

c)

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