Solve the system by substitution. \[ \begin{aligned} x & =-4 y+6 \\ 2 x+9 y & =16\end{aligned} \]
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To solve the system by substitution, we start with the first equation: \[ x = -4y + 6 \] Next, we substitute this expression for \( x \) into the second equation: \[ 2(-4y + 6) + 9y = 16 \] Now, we simplify this equation: \[ -8y + 12 + 9y = 16 \] Combine like terms: \[ (9y - 8y) + 12 = 16 \] \[ y + 12 = 16 \] Next, we isolate \( y \): \[ y = 16 - 12 \] \[ y = 4 \] Now that we have \( y \), we substitute it back into the first equation to find \( x \): \[ x = -4(4) + 6 \] \[ x = -16 + 6 \] \[ x = -10 \] The solution to the system is: \[ x = -10, \; y = 4 \] Thus, the final solution is \( (x, y) = (-10, 4) \).