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If a trend line had the equation \( y=2.7 x-0.17 \), what \( y \)-value would you expect to obtain when \( x \) has the following values? \( \begin{array}{lll}\text { a. } 3 & \text { b. } 0 & \text { c. } 15\end{array} \) a. When \( x=31.7 \) (Type an integer or decimal rounded to the nearest hundredth as needed.) b. When \( x=0, y=-0.17 \). (Type an integer or decimal rounded to the nearest hundrest 1 th as needed.) c. When \( x=15, y=40.33 \). (Type an integer or decimal rounded to the nearest hundredth as needed.) d. When \( x=21.7, y=\square \). (Type an integer or decimal rounded to the nearest hundredth as needed.)

Ask by Mann Lane. in the United States
Feb 03,2025

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When \( x = 21.7 \), \( y = 58.42 \).

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Bonus Knowledge

To find the \( y \)-values corresponding to the given \( x \)-values using the trend line equation \( y=2.7 x-0.17 \), we can follow the formula: a. When \( x=3 \): \[ y = 2.7 \cdot 3 - 0.17 = 8.1 - 0.17 = 7.93 \] b. When \( x=0 \): \[ y = 2.7 \cdot 0 - 0.17 = 0 - 0.17 = -0.17 \] c. When \( x=15 \): \[ y = 2.7 \cdot 15 - 0.17 = 40.5 - 0.17 = 40.33 \] d. When \( x=21.7 \): \[ y = 2.7 \cdot 21.7 - 0.17 = 58.59 - 0.17 = 58.42 \] So, rounding as needed: a. \( y \approx 7.93 \) b. \( y = -0.17 \) c. \( y \approx 40.33 \) d. \( y \approx 58.42 \)

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