Question
A snoll is at the bottom of a well that is 16.5 m deep.
Starting from it climbs up 4.5 m in one hour and
then rest for one hour. When it rests, it slips back 3 m .
If the pattern of climbing and resting continues, at wha
tme will the snail get out of the well?
Starting from it climbs up 4.5 m in one hour and
then rest for one hour. When it rests, it slips back 3 m .
If the pattern of climbing and resting continues, at wha
tme will the snail get out of the well?
Ask by Black Burton. in South Africa
Jan 23,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The snail will take 22 hours to climb out of the well.
Solution
To solve this problem, we need to determine the time it takes for the snail to climb out of the well.
Given:
- Depth of the well: 16.5 m
- Climbing rate: 4.5 m/h
- Slipping rate: 3 m/h
Let’s denote the time it takes for the snail to climb out of the well as
hours.
The snail climbs 4.5 m in one hour and then slips back 3 m in the next hour. This pattern continues until the snail climbs out of the well.
The total distance the snail climbs in one cycle (climbing and resting) is:
Since the snail climbs 1.5 m in one cycle, it will take
cycles to climb out of the well.
The time it takes for the snail to climb out of the well is the number of cycles multiplied by the time it takes for one cycle:
Now, let’s calculate the time it takes for the snail to climb out of the well.
Calculate the value by following steps:
Calculate the value by following steps:
- step0: Calculate:
- step1: Divide the terms:
- step2: Multiply the numbers:
Answered by UpStudy AI and reviewed by a Professional Tutor
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