Question
\[ \sum_{j=1}^{6} 6 j \] How many terms are in the series?
Ask by John Ingram. in South Africa
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
There are 6 terms in the series.
Solution
The given series is:
\[
\sum_{j=1}^{6} 6j
\]
This notation represents the sum of terms where the variable \( j \) takes on integer values starting from 1 up to 6. Let's break it down:
- **Lower limit**: \( j = 1 \)
- **Upper limit**: \( j = 6 \)
- **Term**: \( 6j \)
**Calculating the Number of Terms:**
To determine how many terms are in the series, subtract the lower limit from the upper limit and add 1 (since both endpoints are included):
\[
\text{Number of terms} = (6 - 1) + 1 = 6
\]
**Listing the Terms:**
For clarity, let's list out each term in the series by substituting \( j \) with values from 1 to 6:
1. When \( j = 1 \): \( 6 \times 1 = 6 \)
2. When \( j = 2 \): \( 6 \times 2 = 12 \)
3. When \( j = 3 \): \( 6 \times 3 = 18 \)
4. When \( j = 4 \): \( 6 \times 4 = 24 \)
5. When \( j = 5 \): \( 6 \times 5 = 30 \)
6. When \( j = 6 \): \( 6 \times 6 = 36 \)
So, the series expands to:
\[
6 + 12 + 18 + 24 + 30 + 36
\]
**Conclusion:**
There are **6 terms** in the series.
Reviewed and approved by the UpStudy tutoring team
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Extra Insights
The series \(\sum_{j=1}^{6} 6 j\) is a summation where \(j\) takes values from 1 to 6. Thus, the number of terms in the series corresponds to the number of integer values \(j\) can take, which is 6. So, there are 6 terms in this series.