Question
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8) \( 2|-8+m| \geq 4 \)

Ask by Haynes Medina. in the United States
Dec 05,2024

Real Tutor Solution

Tutor-Verified Answer

Answer

\(m \in (-\infty,6] \cup [10,+\infty)\)

Solution

Solve the equation \( 2|-8+m| \geq 4 \). Solve the inequality by following steps: - step0: Solve for \(m\): \(2\left|-8+m\right|\geq 4\) - step1: Calculate the absolute value: \(2\left|8-m\right|\geq 4\) - step2: Divide both sides: \(\frac{2\left|8-m\right|}{2}\geq \frac{4}{2}\) - step3: Divide the numbers: \(\left|8-m\right|\geq 2\) - step4: Separate into possible cases: \(\begin{align}&8-m\geq 2\\&8-m\leq -2\end{align}\) - step5: Solve the inequality: \(\begin{align}&m\leq 6\\&m\geq 10\end{align}\) - step6: Find the union: \(m \in \left(-\infty,6\right]\cup \left[10,+\infty\right)\) The solution to the inequality \(2|-8+m| \geq 4\) is \(m \in (-\infty,6] \cup [10,+\infty)\).

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The Deep Dive

To solve the inequality \( 2|-8+m| \geq 4 \), we first simplify it by dividing both sides by 2, giving us \( |-8+m| \geq 2 \). This absolute value inequality leads to two cases: \( -8+m \geq 2 \) and \( -8+m \leq -2 \). For the first case, solving \( -8+m \geq 2 \) gives \( m \geq 10 \). For the second case, solving \( -8+m \leq -2 \) yields \( m \leq 6 \). Therefore, the solution to the inequality is \( m \leq 6 \) or \( m \geq 10 \).

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