A machinist must cut 12 strips of metal that are each \( 2 \mathrm{ft} 6 \frac{7}{8} \) in. long. What is the total length needed in inches? The total length of the piece of metal needed is \( \square \mathrm{in} \).
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To find the total length of metal needed, first convert \( 2 \mathrm{ft} 6 \frac{7}{8} \) inches to inches. There are 12 inches in a foot, so: \[ 2 \, \text{ft} = 2 \times 12 = 24 \, \text{inches} \] Now, add the \( 6 \frac{7}{8} \) inches: \[ 24 \, \text{in} + 6 \, \text{in} + \frac{7}{8} \, \text{in} = 30 + \frac{7}{8} \, \text{in} = 30 \frac{7}{8} \, \text{in} \] Next, convert \( 30 \frac{7}{8} \) inches to an improper fraction: \[ 30 \frac{7}{8} = \frac{240 + 7}{8} = \frac{247}{8} \, \text{inches} \] Now, multiply this length by the number of strips (12): \[ \left(\frac{247}{8} \times 12\right) = \frac{247 \times 12}{8} = \frac{2964}{8} = 370.5 \, \text{in} \] So, the total length needed is \( 370.5 \, \text{in} \).