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8) Determine if the lengths 3,9 , and 10 form an acute, right, or obtuse triangle, or if they do-not form a triangle at all. not a triangle acute right obtuse

Ask by Mcfarlane Riley. in the United States
Jan 24,2025

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Answer

The triangle with sides 3, 9, and 10 is an obtuse triangle.

Solution

To determine whether the lengths **3, 9, and 10** form an acute, right, or obtuse triangle (or do not form a triangle at all), follow these steps: ### 1. **Check the Triangle Inequality Theorem** A set of three lengths can form a triangle if the sum of any two sides is greater than the third side. - **3 + 9 > 10?** \( 12 > 10 \) → **True** - **3 + 10 > 9?** \( 13 > 9 \) → **True** - **9 + 10 > 3?** \( 19 > 3 \) → **True** Since all three conditions are true, the lengths **3, 9, and 10** can form a triangle. ### 2. **Determine the Type of Triangle** To determine whether the triangle is acute, right, or obtuse, use the **Pythagorean Theorem**: - Let **c** be the longest side. In this case, \( c = 10 \). - Let **a** and **b** be the other two sides. Here, \( a = 3 \) and \( b = 9 \). Compute \( c^2 \) and \( a^2 + b^2 \): - \( c^2 = 10^2 = 100 \) - \( a^2 + b^2 = 3^2 + 9^2 = 9 + 81 = 90 \) **Compare the two values:** - If \( c^2 = a^2 + b^2 \), the triangle is **right-angled**. - If \( c^2 < a^2 + b^2 \), the triangle is **acute**. - If \( c^2 > a^2 + b^2 \), the triangle is **obtuse**. Here, \( 100 > 90 \), so \( c^2 > a^2 + b^2 \). ### **Conclusion:** The triangle with sides **3, 9, and 10** is an **obtuse** triangle. **Answer:** **obtuse**

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To determine if the lengths 3, 9, and 10 can form a triangle, we can use the triangle inequality theorem, which states that the sum of the lengths of any two sides must be greater than the length of the remaining side. Here, 3 + 9 = 12, which is greater than 10; 3 + 10 = 13, which is greater than 9; and 9 + 10 = 19, which is greater than 3. Since all conditions are satisfied, these sides do indeed form a triangle! Next, to classify the triangle, we utilize the Pythagorean theorem. If the square of the longest side (10) is greater than the sum of the squares of the other two sides (3 and 9), then it's an obtuse triangle. Calculating: 10² = 100 and 3² + 9² = 9 + 81 = 90. Since 100 > 90, this triangle is obtuse!

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