Multiply and simplify $$ \left(3 x^{2}-7 x-5\right)\left(2 x^{2}-10 x-4\right) $$

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Calculate or simplify the expression $$ (3x^2-7x-5)(2x^2-10x-4) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\left(3x^{2}-7x-5ight)\left(2x^{2}-10x-4ight)$$
- step1: Apply the distributive property:
  $$3x^{2}	imes 2x^{2}-3x^{2}	imes 10x-3x^{2}	imes 4-7x	imes 2x^{2}-\left(-7x	imes 10xight)-\left(-7x	imes 4ight)-5	imes 2x^{2}-\left(-5	imes 10xight)-\left(-5	imes 4ight)$$
- step2: Multiply the terms:
  $$6x^{4}-30x^{3}-12x^{2}-14x^{3}-\left(-70x^{2}ight)-\left(-28xight)-10x^{2}-\left(-50xight)-\left(-20ight)$$
- step3: Remove the parentheses:
  $$6x^{4}-30x^{3}-12x^{2}-14x^{3}+70x^{2}+28x-10x^{2}+50x+20$$
- step4: Subtract the terms:
  $$6x^{4}-44x^{3}+48x^{2}+78x+20$$
The multiplication and simplification of $$ \left(3 x^{2}-7 x-5ight)\left(2 x^{2}-10 x-4ight) $$ results in $$ 6x^{4}-44x^{3}+48x^{2}+78x+20 $$.
The simplified expression is $$ 6x^{4}-44x^{3}+48x^{2}+78x+20 $$.

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