WCTICe Work out the value of each expression when \( a=2, b=-3, c=4 \) and \( d=-5 \). \( \left.\begin{array}{llll}\text { a } a+2 b & \text { b } & b d-10 & \text { c } \\ \text { d } a b+c d & \text { e } & c d^{2}+a b & 4 b+2 a \\ \text { g } 20-a^{3} & \text { h } & \frac{b c}{a}+d & \text { f }\end{array}\right] \frac{d}{2}-a \) This is part of Malik's homework.

Let's evaluate each expression step by step using the given values \( a=2, b=-3, c=4, d=-5 \). ### Step 1: Evaluate each expression 1. **Expression \( a + 2b \)**: \[ a + 2b = 2 + 2(-3) = 2 - 6 = -4 \] 2. **Expression \( b \)**: \[ b = -3 \] 3. **Expression \( bd - 10 \)**: \[ bd - 10 = (-3)(-5) - 10 = 15 - 10 = 5 \] 4. **Expression \( d \cdot ab + cd \)**: \[ d \cdot ab + cd = (-5)(2)(-3) + (4)(-5) = 30 - 20 = 10 \] 5. **Expression \( e \)** (not defined in the problem, so we will skip it). 6. **Expression \( cd^2 + ab \)**: \[ cd^2 + ab = (4)(-5)^2 + (2)(-3) = 4 \cdot 25 - 6 = 100 - 6 = 94 \] 7. **Expression \( 4b + 2a \)**: \[ 4b + 2a = 4(-3) + 2(2) = -12 + 4 = -8 \] 8. **Expression \( 20 - a^3 \)**: \[ 20 - a^3 = 20 - (2)^3 = 20 - 8 = 12 \] 9. **Expression \( h \)** (not defined in the problem, so we will skip it). 10. **Expression \( \frac{bc}{a} + d \)**: \[ \frac{bc}{a} + d = \frac{(-3)(4)}{2} + (-5) = \frac{-12}{2} - 5 = -6 - 5 = -11 \] 11. **Expression \( f \)** (not defined in the problem, so we will skip it). ### Step 2: Compile the results Now we have the evaluated expressions: - \( a + 2b = -4 \) - \( b = -3 \) - \( bd - 10 = 5 \) - \( d \cdot ab + cd = 10 \) - \( cd^2 + ab = 94 \) - \( 4b + 2a = -8 \) - \( 20 - a^3 = 12 \) - \( \frac{bc}{a} + d = -11 \) ### Step 3: Substitute into the final expression Now we substitute these values into the final expression: \[ \frac{d}{2} - a \] Substituting \( d = -5 \) and \( a = 2 \): \[ \frac{-5}{2} - 2 = -\frac{5}{2} - \frac{4}{2} = -\frac{9}{2} \] ### Final Answer The final value of the expression is: \[ -\frac{9}{2} \]