Question
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5. A sequence is defined by \( f(1)=3 \) and \( f(n)=2 \cdot f(n-1) \) for \( n \geq 2 \). Which of the \( \quad \) * 1 point following statements defines the \( n \)-th term of \( f \) ?

Ask by Higgins Chan. in the United States
Jan 27,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The \( n \)-th term of the sequence is \( f(n) = 3 \times 2^{n-1} \).

Solution

To find the \( n \)-th term of the sequence defined by \( f(1) = 3 \) and \( f(n) = 2 \cdot f(n-1) \) for \( n \geq 2 \), we can recognize that this is a geometric sequence where each term is twice the previous term. The general formula for the \( n \)-th term of a geometric sequence is: \[ f(n) = f(1) \cdot r^{n-1} \] where \( r \) is the common ratio. In this case, \( r = 2 \) and \( f(1) = 3 \). Plugging in these values: \[ f(n) = 3 \cdot 2^{n-1} \] **Answer:** For all \( n \geq 1 \), the \( n \)-th term is \( f(n) = 3 \times 2^{\,n-1} \).

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The Deep Dive

The sequence you've mentioned is actually geometric in nature! Starting with \( f(1) = 3 \), and applying the recursive formula repeatedly, we can see a pattern forming. Each term is double the previous one, which means \( f(n) = 3 \cdot 2^{n-1} \). So if you want to find any \( n \)-th term in this series, just plug \( n \) into this formula and you’ll have your answer! This type of sequence isn’t just an abstract concept; it pops up in real-world applications like financial calculations for compound interest or even in programming algorithms where iterative doubling occurs. Knowing how to derive these kinds of formulas can save you time and effort, whether it's in school or when you’re budgeting for your next big purchase!

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