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V659. \( 5(x+2)5(1-x) \) \( \vee 661.7(1-x)<20-6(x+3) \)

Ask by Daniels Hill. in Russia
Jan 23,2025

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**Задача V659:** \( x < -10 \) **Задача 660:** \( x > -6 \) **Задача 661:** \( x > 5 \)

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Bonus Knowledge

To solve the first inequality, \(5(x + 2) < x - 2(5 - x)\), first distribute the terms: \(5x + 10 < x - 10 + 2x\). Combine like terms to get: \(5x + 10 < 3x - 10\). Subtract \(3x\) from both sides to arrive at \(2x + 10 < -10\), and then isolate \(x\) to find \(x < -10\). For the second one, \(2 - 3(x - 5) > 5(1 - x)\), start by expanding: \(2 - 3x + 15 > 5 - 5x\). This simplifies to \(-3x + 17 > 5 - 5x\). Bring like terms together: \(2x > -12\) leads to \(x > -6\). And lastly, solve \(7(1 - x) < 20 - 6(x + 3)\) by distributing to get \(7 - 7x < 20 - 6x - 18\). This simplifies to \(-7x < 2 - 20\), or \(-7x < -18\), which gives \(x > \frac{18}{7}\). Happy solving!

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