(e) \( 20 \frac{2}{3} \mathrm{~cm} \times 8 \frac{1}{3} \mathrm{~cm} \times 5 \frac{2}{3} \mathrm{~cm} \) (g) \( 12.5 \mathrm{~cm} \times 12.7 \mathrm{~cm} \times 2.6 \mathrm{~cm} \)

Sure, let's calculate the volumes for both parts (e) and (g) step by step. --- ### **Problem (e)** **Dimensions:** - Length: \( 20 \frac{2}{3} \) cm - Width: \( 8 \frac{1}{3} \) cm - Height: \( 5 \frac{2}{3} \) cm **Step 1: Convert Mixed Numbers to Improper Fractions** 1. **Length:** \[ 20 \frac{2}{3} = \left(20 \times 3 + 2\right) \frac{1}{3} = \frac{62}{3} \text{ cm} \] 2. **Width:** \[ 8 \frac{1}{3} = \left(8 \times 3 + 1\right) \frac{1}{3} = \frac{25}{3} \text{ cm} \] 3. **Height:** \[ 5 \frac{2}{3} = \left(5 \times 3 + 2\right) \frac{1}{3} = \frac{17}{3} \text{ cm} \] **Step 2: Calculate the Volume** \[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} = \frac{62}{3} \times \frac{25}{3} \times \frac{17}{3} \] \[ \text{Volume} = \frac{62 \times 25 \times 17}{3 \times 3 \times 3} = \frac{26,350}{27} \approx 975.93 \text{ cm}^3 \] --- ### **Problem (g)** **Dimensions:** - Length: 12.5 cm - Width: 12.7 cm - Height: 2.6 cm **Step 1: Calculate the Volume** Since all dimensions are already in decimal form, multiply them directly: \[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} = 12.5 \times 12.7 \times 2.6 \] **Step 2: Perform the Multiplication** 1. Multiply Length and Width: \[ 12.5 \times 12.7 = 158.75 \] 2. Multiply the result by Height: \[ 158.75 \times 2.6 = 412.75 \text{ cm}^3 \] --- ### **Final Answers** - **Problem (e):** The volume is approximately **975.93 cm³**. - **Problem (g):** The volume is **412.75 cm³**.