2. Gabriel, Henry and Irene have $$ \$ 320 $$ altogether. Henry has $$ \$ 20 $$ more than Gabriel. Irene has twice as much as Henry. How much money does Irene have?

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1. Let $$ G $$ be Gabriel's amount, $$ H $$ be Henry's amount, and $$ I $$ be Irene's amount.

2. Based on the problem, we have the following equations:
   - Total amount: 
     $$
     G + H + I = 320
     $$
   - Henry has $$ \$20 $$ more than Gabriel:
     $$
     H = G + 20
     $$
   - Irene has twice as much as Henry:
     $$
     I = 2H
     $$

3. Substitute the expressions for $$ H $$ and $$ I $$ in terms of $$ G $$ into the first equation:
   $$
   G + (G+20) + 2(G+20) = 320
   $$

4. Simplify the equation:
   $$
   G + G + 20 + 2G + 40 = 320
   $$
   $$
   4G + 60 = 320
   $$

5. Solve for $$ G $$:
   $$
   4G = 320 - 60
   $$
   $$
   4G = 260
   $$
   $$
   G = \frac{260}{4} = 65
   $$

6. Find Henry's amount:
   $$
   H = G + 20 = 65 + 20 = 85
   $$

7. Find Irene's amount:
   $$
   I = 2H = 2 \times 85 = 170
   $$

Irene has $$\$170$$.
Irene has \$170.

Gabriel, Henry and Irene have altogether. Henry has more than
Gabriel. Irene has twice as much as Henry. How much money does Irene
have?

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Gabriel, Henry and Irene have altogether. Henry has more than Gabriel. Irene has twice as much as Henry. How much money does Irene have?