Question
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iven that \( 3^{2 x+3} \times 9^{x}=3^{4-3 y} \), find an expression for \( y \) in terms of \( x \).

Ask by Carrillo Sullivan. in New Zealand
Jan 21,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\( y = \frac{1 - 4x}{3} \)

Solution

To solve for \( y \) in the equation: \[ 3^{2x + 3} \times 9^x = 3^{4 - 3y} \] follow these steps: 1. **Express \( 9^x \) in terms of base 3:** Since \( 9 = 3^2 \), we can rewrite \( 9^x \) as \( (3^2)^x = 3^{2x} \). 2. **Combine the exponents on the left side:** \[ 3^{2x + 3} \times 3^{2x} = 3^{(2x + 3) + 2x} = 3^{4x + 3} \] 3. **Set the exponents equal to each other:** \[ 4x + 3 = 4 - 3y \] 4. **Solve for \( y \):** \[ 4x + 3 - 4 = -3y \\ 4x - 1 = -3y \\ y = \frac{1 - 4x}{3} \] So, the expression for \( y \) in terms of \( x \) is: \[ y = \frac{1 - 4x}{3} \] Answer: After simplifying, y is (1 minus four x) divided by three. Thus, y = ( 1 − 4x ) ⁄ 3

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Beyond the Answer

To solve the equation \( 3^{2x+3} \times 9^{x} = 3^{4-3y} \), we start by rewriting \(9^{x}\) in terms of base \(3\): \[ 9^{x} = (3^2)^{x} = 3^{2x}. \] Now, we can substitute this back into the original equation: \[ 3^{2x+3} \times 3^{2x} = 3^{4-3y}. \] Next, we combine the powers on the left-hand side: \[ 3^{(2x+3) + 2x} = 3^{4-3y}. \] This simplifies to: \[ 3^{4x + 3} = 3^{4-3y}. \] Since the bases are the same, we can equate the exponents: \[ 4x + 3 = 4 - 3y. \] Now, we can solve for \(y\): \[ 3y = 4 - (4x + 3), \] \[ 3y = 4 - 4x - 3, \] \[ 3y = 1 - 4x. \] Dividing everything by 3 gives us: \[ y = \frac{1 - 4x}{3}. \] Thus, the expression for \(y\) in terms of \(x\) is: \[ y = \frac{1 - 4x}{3}. \]

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