iven that \( 3^{2 x+3} \times 9^{x}=3^{4-3 y} \), find an expression for \( y \) in terms of \( x \).
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To solve the equation \( 3^{2x+3} \times 9^{x} = 3^{4-3y} \), we start by rewriting \(9^{x}\) in terms of base \(3\): \[ 9^{x} = (3^2)^{x} = 3^{2x}. \] Now, we can substitute this back into the original equation: \[ 3^{2x+3} \times 3^{2x} = 3^{4-3y}. \] Next, we combine the powers on the left-hand side: \[ 3^{(2x+3) + 2x} = 3^{4-3y}. \] This simplifies to: \[ 3^{4x + 3} = 3^{4-3y}. \] Since the bases are the same, we can equate the exponents: \[ 4x + 3 = 4 - 3y. \] Now, we can solve for \(y\): \[ 3y = 4 - (4x + 3), \] \[ 3y = 4 - 4x - 3, \] \[ 3y = 1 - 4x. \] Dividing everything by 3 gives us: \[ y = \frac{1 - 4x}{3}. \] Thus, the expression for \(y\) in terms of \(x\) is: \[ y = \frac{1 - 4x}{3}. \]