7 Complete the following. \( 10 \times 79 \) \( \begin{array}{ll}\text { a } \vee \text { If } 22+18=40 \text {, then } 40-18=\square & \text { b }{ }^{\vee} \text { If } 25+37=62 \text {, then } \square-\square= \\ \text { c If } 15 \times 20=300 \text {, then } 300 \div 20=\square & \text { d If } 12 \times 16=192 \text {, then } \square \div 12=\end{array} \)

Let's solve each part step by step. ### Part a Given: \[ 22 + 18 = 40 \] We need to find: \[ 40 - 18 = \square \] **Calculation:** \[ 40 - 18 = 22 \] So, the answer for part a is: \[ \boxed{22} \] ### Part b Given: \[ 25 + 37 = 62 \] We need to find: \[ \square - \square = \] To express this, we can use the numbers we have: Let \( x = 25 \) and \( y = 37 \). Then we can write: \[ 62 - 25 = 37 \] or \[ 62 - 37 = 25 \] So, we can fill in the blanks as: \[ 62 - 25 = 37 \] or \[ 62 - 37 = 25 \] Thus, the answer for part b can be represented as: \[ \boxed{62 - 25 = 37} \] or \[ \boxed{62 - 37 = 25} \] ### Part c Given: \[ 15 \times 20 = 300 \] We need to find: \[ 300 \div 20 = \square \] **Calculation:** \[ 300 \div 20 = 15 \] So, the answer for part c is: \[ \boxed{15} \] ### Part d Given: \[ 12 \times 16 = 192 \] We need to find: \[ \square \div 12 = \] To find this, we can express it as: Let \( x = 192 \). Then we can write: \[ 192 \div 12 = \square \] **Calculation:** \[ 192 \div 12 = 16 \] So, the answer for part d is: \[ \boxed{16} \] ### Summary of Answers: - a: \( \boxed{22} \) - b: \( \boxed{62 - 25 = 37} \) or \( \boxed{62 - 37 = 25} \) - c: \( \boxed{15} \) - d: \( \boxed{16} \)