Divide. (Simplify your answer completely.) $$ \frac{x^{2}+3 x-18}{x^{2}+2 x-15} \div \frac{x^{2}+2 x-24}{x^{2}+3 x-4} $$

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Calculate or simplify the expression $$ (x^{2}+3x-18)/(x^{2}+2x-15) \div (x^{2}+2x-24)/(x^{2}+3x-4) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{\frac{\left(x^{2}+3x-18ight)}{\left(x^{2}+2x-15ight)}\div \left(x^{2}+2x-24ight)}{\left(x^{2}+3x-4ight)}$$
- step1: Remove the parentheses:
  $$\frac{\frac{x^{2}+3x-18}{x^{2}+2x-15}\div \left(x^{2}+2x-24ight)}{x^{2}+3x-4}$$
- step2: Divide the terms:
  $$\frac{\frac{x+6}{x+5}\div \left(x^{2}+2x-24ight)}{x^{2}+3x-4}$$
- step3: Divide the terms:
  $$\frac{\frac{1}{\left(x+5ight)\left(x-4ight)}}{x^{2}+3x-4}$$
- step4: Multiply by the reciprocal:
  $$\frac{1}{\left(x+5ight)\left(x-4ight)}	imes \frac{1}{x^{2}+3x-4}$$
- step5: Multiply the terms:
  $$\frac{1}{\left(x+5ight)\left(x-4ight)\left(x^{2}+3x-4ight)}$$
- step6: Calculate:
  $$\frac{1}{x^{4}+4x^{3}-21x^{2}-64x+80}$$
The result of dividing the given expressions is $$ \frac{1}{x^{4}+4x^{3}-21x^{2}-64x+80} $$.
The simplified result is $$ \frac{1}{x^{4}+4x^{3}-21x^{2}-64x+80} $$.

Divide. (Simplify your answer completely.)

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