Consider the following two linear equations. $$ y=-8 x-11 $$ Solve for the point of intersection using substitution (8)

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To find the point of intersection of the two linear equations, we will use substitution. However, it seems that only one equation is provided. For a complete solution, we need a second equation.

Assuming the second equation is $$ y = mx + b $$ (where $$ m $$ and $$ b $$ are constants), we can proceed with the substitution method.

Let's denote the first equation as:
1. $$ y = -8x - 11 $$

Now, if we had a second equation, we would substitute the expression for $$ y $$ from the first equation into the second equation.

For example, if the second equation were $$ y = 2x + 3 $$, we would substitute as follows:

1. Substitute $$ y $$ in the second equation:
   $$
   -8x - 11 = 2x + 3
   $$

2. Solve for $$ x $$:
   $$
   -8x - 2x = 3 + 11
   $$
   $$
   -10x = 14
   $$
   $$
   x = -\frac{14}{10} = -\frac{7}{5}
   $$

3. Substitute $$ x $$ back into the first equation to find $$ y $$:
   $$
   y = -8\left(-\frac{7}{5}\right) - 11
   $$
   $$
   y = \frac{56}{5} - 11
   $$
   $$
   y = \frac{56}{5} - \frac{55}{5} = \frac{1}{5}
   $$

Thus, the point of intersection would be $$ \left(-\frac{7}{5}, \frac{1}{5}\right) $$.

Please provide the second equation so I can solve for the exact point of intersection.
Cannot determine the point of intersection without a second equation.

Consider the following two linear equations.

Solve for the point of intersection using substitution (8)

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Consider the following two linear equations. Solve for the point of intersection using substitution (8)