Given the points \( (2,-7) \) and \( (0,4) \) on a line, find its equation in the form \( y=m x+b \). \( y=\square \)
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To find the equation of the line in slope-intercept form \( y = mx + b \), we first need to calculate the slope \( m \) using the two points \( (2, -7) \) and \( (0, 4) \). The formula for slope is given by: \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 - (-7)}{0 - 2} = \frac{4 + 7}{-2} = \frac{11}{-2} = -\frac{11}{2} \] Now, we can use one of the points, say \( (0, 4) \), to find the y-intercept \( b \). Since the x-coordinate is 0, we know the y-intercept is directly \( b = 4 \). Now we can write the equation in slope-intercept form: \[ y = -\frac{11}{2}x + 4 \] So, the equation of the line is: \( y = -\frac{11}{2}x + 4 \)