Simplify the polynomial, then evaluate for $$ x=-1 $$ $$ 3 x^{2}-4+2 x-1+x^{2} $$ $$ 3 x^{2}+3 x-5 ;-5 $$ $$ 6 x^{2}-5 ; 1 $$ $$ 4 x^{2}+2 x-5 ;-3 $$ $$ 4 x^{2}+2 x-5 ;-11 $$

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Let's simplify the given polynomial and then evaluate it for $$ x = -1 $$.

### Given Polynomial:
$$ 3x^{2} - 4 + 2x - 1 + x^{2} $$

### Step 1: Combine Like Terms
- **Quadratic Terms ($$ x^{2} $$):**
  $$ 3x^{2} + x^{2} = 4x^{2} $$

- **Linear Terms ($$ x $$):**
  $$ 2x $$ (No other $$ x $$ terms to combine)

- **Constant Terms:**
  $$ -4 - 1 = -5 $$

### Simplified Polynomial:
$$ 4x^{2} + 2x - 5 $$

### Step 2: Evaluate at $$ x = -1 $$
Substitute $$ x = -1 $$ into the simplified polynomial:
$$
\begin{align*}
4(-1)^{2} + 2(-1) - 5 &= 4(1) - 2 - 5 \
&= 4 - 2 - 5 \
&= -3
\end{align*}
$$

### Final Answer:
$$ 4x^{2} + 2x - 5 \quad \text{evaluated at} \quad x = -1 \quad \text{is} \quad -3 $$

**Correct Option:**
$$ 4x^{2} + 2x - 5 ; \, -3 $$
The simplified polynomial is $$ 4x^{2} + 2x - 5 $$. When evaluated at $$ x = -1 $$, the result is $$ -3 $$.

Simplify the polynomial, then evaluate for \( x=-1 \) \( 3 x^{2}-4+2 x-1+x^{2} \) \( 3 x^{2}+3 x-5 ;-5 \) \( 6 x^{2}-5 ; 1 \) \( 4 x^{2}+2 x-5 ;-3 \) \( 4 x^{2}+2 x-5 ;-11 \)

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