\begin{tabular}{|l|l|} Write the arithmetic sequence $$ -14,-11,-8,-5, \ldots $$ in the standard form: \ $$ a_{n}=\square $$ Preview \end{tabular}$$ | $$

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To write the arithmetic sequence $$ -14, -11, -8, -5, \ldots $$ in standard form, we first need to identify the first term and the common difference.

1. **First term ($$ a_1 $$)**: The first term of the sequence is $$ -14 $$.
2. **Common difference ($$ d $$)**: To find the common difference, we subtract the first term from the second term:
   $$
   d = -11 - (-14) = -11 + 14 = 3
   $$

Now that we have the first term and the common difference, we can write the general term of the arithmetic sequence in standard form. The formula for the $$ n $$-th term of an arithmetic sequence is given by:
$$
a_n = a_1 + (n - 1) \cdot d
$$

Substituting the values we found:
- $$ a_1 = -14 $$
- $$ d = 3 $$

The formula becomes:
$$
a_n = -14 + (n - 1) \cdot 3
$$

Now, we can simplify this expression:
$$
a_n = -14 + 3(n - 1)
$$
$$
a_n = -14 + 3n - 3
$$
$$
a_n = 3n - 17
$$

Thus, the standard form of the arithmetic sequence is:
$$
a_n = 3n - 17
$$
$$ a_n = 3n - 17 $$

Write the arithmetic sequence in the standard form:

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