Question
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If \( \frac{4}{41} \) of all rabbits in a country are in one state and \( \frac{1}{6} \) of the rabbits are in a different state, vhat fotal fractional part of the rabbit population is in those two states? The total fractional part of the rabbit population living in the two states is (Type an integer or a simplified fraction.)

Ask by Rose Riley. in the United States
Jan 25,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The total fractional part of the rabbit population living in the two states is \( \frac{65}{246} \).

Solution

To determine the total fractional part of the rabbit population residing in the two states, you'll need to add the two given fractions: \[ \frac{4}{41} \quad \text{and} \quad \frac{1}{6} \] ### Step 1: Find a Common Denominator The first step is to find a common denominator for the two fractions. The least common denominator (LCD) of 41 and 6 is: \[ 41 \times 6 = 246 \] ### Step 2: Convert Each Fraction Convert each fraction to an equivalent fraction with the denominator of 246. \[ \frac{4}{41} = \frac{4 \times 6}{41 \times 6} = \frac{24}{246} \] \[ \frac{1}{6} = \frac{1 \times 41}{6 \times 41} = \frac{41}{246} \] ### Step 3: Add the Fractions Now, add the two fractions: \[ \frac{24}{246} + \frac{41}{246} = \frac{24 + 41}{246} = \frac{65}{246} \] ### Step 4: Simplify the Fraction Check if the fraction can be simplified by finding the greatest common divisor (GCD) of 65 and 246. - **Factors of 65:** 1, 5, 13, 65 - **Factors of 246:** 1, 2, 3, 6, 41, 82, 123, 246 The only common factor is **1**, so the fraction is already in its simplest form. \[ \frac{65}{246} \] ### Final Answer The total fractional part of the rabbit population living in the two states is: \[ \boxed{\dfrac{65}{246}} \]

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To find the total fractional part of the rabbit population in the two states, we need to add the two fractions together: \[ \frac{4}{41} + \frac{1}{6} \] To do this, we first need to find a common denominator. The least common multiple (LCM) of 41 and 6 is 246. Now, we convert each fraction: \[ \frac{4}{41} = \frac{4 \times 6}{41 \times 6} = \frac{24}{246} \] \[ \frac{1}{6} = \frac{1 \times 41}{6 \times 41} = \frac{41}{246} \] Now we can add the two fractions: \[ \frac{24}{246} + \frac{41}{246} = \frac{24 + 41}{246} = \frac{65}{246} \] Next, we simplify the fraction \(\frac{65}{246}\). Both 65 and 246 can be divided by 13: \[ \frac{65 \div 13}{246 \div 13} = \frac{5}{18} \] So, the total fractional part of the rabbit population living in the two states is \(\frac{5}{18}\).

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