nd the $$ x $$-intercepts and $$ y $$-intercept of the following function. $$ f(x)=(x-4)(x-2)(3 x+15) $$ Nrite your answer in coordinate pairs of the form $$ (x, y) $$ Provide your answer below: $$ x $$-intercept: $$ (\square),(\square) $$ and $$ (\square) \cdot y $$-intercept: $$ (\square) $$

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To find the $$ x $$-intercepts and $$ y $$-intercept of the function $$ f(x) = (x-4)(x-2)(3x+15) $$, follow these steps:

### $$ x $$-Intercepts:
The $$ x $$-intercepts occur where $$ f(x) = 0 $$.

$$
(x - 4)(x - 2)(3x + 15) = 0
$$

Set each factor equal to zero and solve for $$ x $$:

1. $$ x - 4 = 0 $$ → $$ x = 4 $$
2. $$ x - 2 = 0 $$ → $$ x = 2 $$
3. $$ 3x + 15 = 0 $$ → $$ 3x = -15 $$ → $$ x = -5 $$

So, the $$ x $$-intercepts are:
- $$ (4, 0) $$
- $$ (2, 0) $$
- $$ (-5, 0) $$

### $$ y $$-Intercept:
The $$ y $$-intercept occurs where $$ x = 0 $$.

$$
f(0) = (0 - 4)(0 - 2)(3 \times 0 + 15) = (-4)(-2)(15) = 120
$$

So, the $$ y $$-intercept is:
- $$ (0, 120) $$

### Final Answer:
$$ x $$-intercept: $$ (4, 0) $$, $$ (2, 0) $$, and $$ (-5, 0) $$ · $$ y $$-intercept: $$ (0, 120) $$
$$ x $$-intercepts: $$ (4, 0) $$, $$ (2, 0) $$, $$ (-5, 0) $$ $$ y $$-intercept: $$ (0, 120) $$

nd the -intercepts and -intercept of the following function.

Nrite your answer in coordinate pairs of the form
Provide your answer below:
-intercept: and -intercept:

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nd the -intercepts and -intercept of the following function. Nrite your answer in coordinate pairs of the form Provide your answer below: -intercept: and -intercept: