Find equation of line $$ (7,8) $$ and $$ (-8,2) $$

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To find the equation of the line that passes through the points $$ (7, 8) $$ and $$ (-8, 2) $$, we can follow these steps:

1. **Calculate the slope (m)** of the line using the formula:
   $$
   m = \frac{y_2 - y_1}{x_2 - x_1}
   $$
   where $$ (x_1, y_1) = (7, 8) $$ and $$ (x_2, y_2) = (-8, 2) $$.

Substituting the values:
   $$
   m = \frac{2 - 8}{-8 - 7} = \frac{-6}{-15} = \frac{2}{5}
   $$

2. **Use the point-slope form** of the equation of a line, which is:
   $$
   y - y_1 = m(x - x_1)
   $$
   We can use either point; let's use $$ (7, 8) $$:
   $$
   y - 8 = \frac{2}{5}(x - 7)
   $$

3. **Simplify the equation**:
   $$
   y - 8 = \frac{2}{5}x - \frac{14}{5}
   $$
   Adding 8 to both sides:
   $$
   y = \frac{2}{5}x - \frac{14}{5} + 8
   $$
   To combine the constants, convert 8 to a fraction with a denominator of 5:
   $$
   8 = \frac{40}{5}
   $$
   Thus,
   $$
   y = \frac{2}{5}x - \frac{14}{5} + \frac{40}{5} = \frac{2}{5}x + \frac{26}{5}
   $$

4. **Final equation**:
   The equation of the line in slope-intercept form is:
   $$
   y = \frac{2}{5}x + \frac{26}{5}
   $$

Alternatively, if you want the equation in standard form $$ Ax + By = C $$, we can rearrange it:
$$
-\frac{2}{5}x + y = \frac{26}{5}
$$
Multiplying through by 5 to eliminate the fraction:
$$
-2x + 5y = 26
$$
Rearranging gives:
$$
2x - 5y = -26
$$

Thus, the equation of the line can be expressed as:
$$
2x - 5y = -26
$$
The equation of the line is $$ y = \frac{2}{5}x + \frac{26}{5} $$ or $$ 2x - 5y = -26 $$.

Find equation of line and

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