Answer
After 2.5 years, \$500 at 4.7% interest grows to approximately \$558.75 with simple interest and about \$561 with annual compound interest.
Solution
Certainly! It looks like you're interested in calculating the growth of a **\$500** investment at an annual interest rate of **4.7%** over **2.5 years**. Depending on how the interest is applied, there are two primary methods to calculate this:
1. **Simple Interest**
2. **Compound Interest**
Let’s explore both:
---
### 1. Simple Interest
**Simple Interest** calculates interest only on the **principal amount** (the original sum of money).
**Formula:**
\[ \text{Simple Interest (SI)} = P \times r \times t \]
Where:
- \( P \) = Principal amount (\$500)
- \( r \) = Annual interest rate (4.7% or 0.047)
- \( t \) = Time in years (2.5)
**Calculation:**
\[ \text{SI} = 500 \times 0.047 \times 2.5 \]
\[ \text{SI} = 500 \times 0.1175 \]
\[ \text{SI} = \$58.75 \]
**Total Amount After 2.5 Years:**
\[ \text{Total} = P + \text{SI} = 500 + 58.75 = \$558.75 \]
---
### 2. Compound Interest
**Compound Interest** calculates interest on the principal amount **and** on the accumulated interest from previous periods. The frequency of compounding (e.g., annually, semi-annually, quarterly, monthly) affects the total interest earned.
Since the compounding frequency isn't specified, I'll demonstrate **annual compounding**. If you have a different compounding frequency in mind, let me know!
**Formula:**
\[ A = P \times \left(1 + \frac{r}{n}\right)^{n \times t} \]
Where:
- \( A \) = Amount of money accumulated after n years, including interest.
- \( P \) = Principal amount (\$500)
- \( r \) = Annual interest rate (4.7% or 0.047)
- \( n \) = Number of times interest is compounded per year
- \( t \) = Time the money is invested for (2.5 years)
**Assuming Annual Compounding (\( n = 1 \)):**
\[ A = 500 \times \left(1 + \frac{0.047}{1}\right)^{1 \times 2.5} \]
\[ A = 500 \times (1.047)^{2.5} \]
**Calculating \( (1.047)^{2.5} \):**
First, calculate the natural logarithm to handle the exponent:
\[ \ln(1.047) \approx 0.046 \]
\[ 2.5 \times \ln(1.047) \approx 2.5 \times 0.046 = 0.115 \]
\[ e^{0.115} \approx 1.122 \]
So,
\[ A \approx 500 \times 1.122 = \$561 \]
**Total Interest Earned:**
\[ \text{Interest} = A - P = 561 - 500 = \$61 \]
*Note:* The exact amount may vary slightly based on more precise calculations or different compounding frequencies.
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### **Summary**
- **Simple Interest:** \$58.75
- **Compound Interest (Annually):** Approximately \$61
If you have a specific compounding frequency (like monthly or quarterly) or require more precise calculations, please provide those details, and I can adjust the calculations accordingly!
Reviewed and approved by the UpStudy tutoring team
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