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\( \$ 500 \) at \( 4.7 \% \) for \( 2 \frac{1}{2} \) years

Ask by Henry Gordon. in the United States
Jan 22,2025

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After 2.5 years, \$500 at 4.7% interest grows to approximately \$558.75 with simple interest and about \$561 with annual compound interest.

Solution

Certainly! It looks like you're interested in calculating the growth of a **\$500** investment at an annual interest rate of **4.7%** over **2.5 years**. Depending on how the interest is applied, there are two primary methods to calculate this: 1. **Simple Interest** 2. **Compound Interest** Let’s explore both: --- ### 1. Simple Interest **Simple Interest** calculates interest only on the **principal amount** (the original sum of money). **Formula:** \[ \text{Simple Interest (SI)} = P \times r \times t \] Where: - \( P \) = Principal amount (\$500) - \( r \) = Annual interest rate (4.7% or 0.047) - \( t \) = Time in years (2.5) **Calculation:** \[ \text{SI} = 500 \times 0.047 \times 2.5 \] \[ \text{SI} = 500 \times 0.1175 \] \[ \text{SI} = \$58.75 \] **Total Amount After 2.5 Years:** \[ \text{Total} = P + \text{SI} = 500 + 58.75 = \$558.75 \] --- ### 2. Compound Interest **Compound Interest** calculates interest on the principal amount **and** on the accumulated interest from previous periods. The frequency of compounding (e.g., annually, semi-annually, quarterly, monthly) affects the total interest earned. Since the compounding frequency isn't specified, I'll demonstrate **annual compounding**. If you have a different compounding frequency in mind, let me know! **Formula:** \[ A = P \times \left(1 + \frac{r}{n}\right)^{n \times t} \] Where: - \( A \) = Amount of money accumulated after n years, including interest. - \( P \) = Principal amount (\$500) - \( r \) = Annual interest rate (4.7% or 0.047) - \( n \) = Number of times interest is compounded per year - \( t \) = Time the money is invested for (2.5 years) **Assuming Annual Compounding (\( n = 1 \)):** \[ A = 500 \times \left(1 + \frac{0.047}{1}\right)^{1 \times 2.5} \] \[ A = 500 \times (1.047)^{2.5} \] **Calculating \( (1.047)^{2.5} \):** First, calculate the natural logarithm to handle the exponent: \[ \ln(1.047) \approx 0.046 \] \[ 2.5 \times \ln(1.047) \approx 2.5 \times 0.046 = 0.115 \] \[ e^{0.115} \approx 1.122 \] So, \[ A \approx 500 \times 1.122 = \$561 \] **Total Interest Earned:** \[ \text{Interest} = A - P = 561 - 500 = \$61 \] *Note:* The exact amount may vary slightly based on more precise calculations or different compounding frequencies. --- ### **Summary** - **Simple Interest:** \$58.75 - **Compound Interest (Annually):** Approximately \$61 If you have a specific compounding frequency (like monthly or quarterly) or require more precise calculations, please provide those details, and I can adjust the calculations accordingly!

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To understand how much money you'll have after investing $500 at an interest rate of 4.7% for 2.5 years, you can use the formula for compound interest, which is \( A = P(1 + r)^t \). Here, \( P \) is the principal amount, \( r \) is the annual interest rate (in decimal form), and \( t \) is the time in years. Plugging in your values gives you \( A = 500(1 + 0.047)^{2.5} \), leading to a future value of about $567.45! Now, if you're wondering how to avoid any common pitfalls, make sure to double-check if the interest is compounded annually, semi-annually, or monthly! Compounding frequency can significantly change your final amount. Also, don’t forget to convert the interest rate from a percentage to a decimal before calculations—it's a small step that can save you from a big headache later!

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