\begin{tabular}{l} A landscape architect planned a flower garden in the shape of a parallelogram. If the \\ base and height are multiplied by \( \frac{1}{2} \) to create a new parallelogram, what is the new \\ area? Round to the nearest unit, if necessary. \\ \hline \( 120 \mathrm{ft}^{2} \)\end{tabular}

The area of a parallelogram is calculated using the formula \( \text{Area} = \text{base} \times \text{height} \). If the base and height are both multiplied by \( \frac{1}{2} \), the new area becomes: \[ \text{New Area} = \left(\frac{1}{2} \times \text{base}\right) \times \left(\frac{1}{2} \times \text{height}\right) = \frac{1}{4} \times (\text{base} \times \text{height}) = \frac{1}{4} \times \text{Original Area} \] Given that the original area is \( 120 \, \text{ft}^2 \): \[ \text{New Area} = \frac{1}{4} \times 120 \, \text{ft}^2 = 30 \, \text{ft}^2 \] So, the new area of the parallelogram after the changes is \( 30 \, \text{ft}^2 \).