Question
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Factor the polynomial: \[ x^{2}+8 x+16 \]

Ask by Pollard Wagner. in the United States
Feb 04,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\[ (x + 4)^2 \]

Solution

To factor the quadratic polynomial \( x^{2} + 8x + 16 \), follow these steps: 1. **Identify the coefficients**: - \( a = 1 \) (coefficient of \( x^2 \)) - \( b = 8 \) (coefficient of \( x \)) - \( c = 16 \) (constant term) 2. **Find two numbers that multiply to \( c \) (16) and add up to \( b \) (8)**: - The numbers are **4 and 4** because: \[ 4 \times 4 = 16 \quad \text{and} \quad 4 + 4 = 8 \] 3. **Write the factored form using these numbers**: \[ x^{2} + 8x + 16 = (x + 4)(x + 4) \] - This can also be written as: \[ (x + 4)^2 \] **Final Answer**: \[ (x + 4)^2 \]

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Sure thing! Here’s a fun breakdown of the factorization: This polynomial, \( x^{2}+8x+16 \), is a perfect square. You may notice that the coefficients nicely fit into the form \( (a + b)^2 = a^2 + 2ab + b^2 \). In this case, you can rewrite it as \( (x + 4)^2 \), since \( 4^2 = 16 \) and \( 2 \cdot 4 \cdot x = 8x \). So the factored form is: \[ (x + 4)(x + 4) \] or simply \( (x + 4)^2 \). Now you have a neat and tidy way to express this polynomial!

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