3. \( 28 c k \) is standing at the top of a lookout tower and spots a water fountain below. If the lookout tower Is 75 feet tall and the angle of depression is \( 28^{\circ} \), what is the horizontal distance between Zack and the water fountain?
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To find the horizontal distance between Zack and the water fountain, you can use trigonometry. Since the angle of depression is \(28^{\circ}\), the corresponding angle of elevation from the fountain to Zack is also \(28^{\circ}\). We'll use the tangent function, which relates the opposite side (the height of the tower) to the adjacent side (the horizontal distance we want to find): \[ \tan(28^{\circ}) = \frac{\text{height}}{\text{horizontal distance}} = \frac{75 \text{ feet}}{d} \] Rearranging gives: \[ d = \frac{75 \text{ feet}}{\tan(28^{\circ})} \] Calculating \( \tan(28^{\circ}) \) (approximately \(0.5317\)) yields: \[ d \approx \frac{75}{0.5317} \approx 141.77 \text{ feet} \] So, the horizontal distance between Zack and the water fountain is approximately \(141.77\) feet.