6$$ ^{\circ} $$ (MAUÁ-SP) $$ 2 \% $$ de A, onde $$ A=\left(1+\frac{1}{2}\right)^{2}: \frac{3}{4}-\frac{2}{3} \cdot\left(1-\frac{1}{4}\right) \text { é: } $$ $$ \begin{array}{lllll}\text { a) } 1 & \text { b) } \frac{1}{5} & \text { c) } \frac{1}{20} & \text { d) } 2,3 & \text { e) } \frac{2}{5}\end{array} $$

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$$
A=\frac{\left(1+\frac{1}{2}\right)^2}{\frac{3}{4}}-\frac{2}{3}\cdot\left(1-\frac{1}{4}\right).
$$

1. Calcular $$1+\frac{1}{2}$$:
$$
1+\frac{1}{2}=\frac{3}{2}.
$$

2. Elevar ao quadrado:
$$
\left(\frac{3}{2}\right)^2=\frac{9}{4}.
$$

3. Dividir por $$\frac{3}{4}$$:
$$
\frac{\frac{9}{4}}{\frac{3}{4}}=\frac{9}{4}\cdot\frac{4}{3}=3.
$$

4. Calcular $$1-\frac{1}{4}$$:
$$
1-\frac{1}{4}=\frac{3}{4}.
$$

5. Multiplicar por $$\frac{2}{3}$$:
$$
\frac{2}{3}\cdot\frac{3}{4}=\frac{2\cdot3}{3\cdot4}=\frac{6}{12}=\frac{1}{2}.
$$

6. Subtrair os resultados para obter $$A$$:
$$
A=3-\frac{1}{2}=\frac{6}{2}-\frac{1}{2}=\frac{5}{2}.
$$

7. Calcular $$2\%$$ de $$A$$:
$$
2\%\ \text{de}\ A=\frac{2}{100}\cdot\frac{5}{2}=\frac{10}{200}=\frac{1}{20}.
$$

Logo, a resposta é $$\frac{1}{20}$$.
A resposta é $$\frac{1}{20}$$, opção c).

6 (MAUÁ-SP) de A, onde

$é$

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